(y^2+y+3)=4+y^2+5y

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Solution for (y^2+y+3)=4+y^2+5y equation: 



(y^2+y+3)=4+y^2+5y

We move all terms to the left:

(y^2+y+3)-(4+y^2+5y)=0

We get rid of parentheses

-y^2+y^2-5y+y-4+3=0

We add all the numbers together, and all the variables

-4y-1=0

We move all terms containing y to the left, all other terms to the right

-4y=1

y=1/-4

y=-1/4

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